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100 " mL of " 0.2 M Kal`(OH)_(2)CO_(3)` solution is completely neutralised by a standard solution of `(M)/(4)H_(2)C_(2)O_(4)`. Which of the following is/are wrong?A. The volume of `H_(2)C_(2)O_(4)` required is 160 mL.B. the volume of `H_(2)C_(2)O_(4)` required 80 mL.C. The normality of `KAl` `(OH)_(2)CO_(3)` is 0.4 ND. It is a redox reaction. |
Answer» Correct Answer - B::C::D n factor for `overset(+1+3)(Kal)(overset(-2)(OH))_(2)overset(-2)(CO_(3))` is the total positive or negative charge`=4`. n factor for `H_(2)C_(2)O_(4)=2(2H^(o+)` ions) It is an acid-base titration `m" Eq of "Kal(OH)_(2)CO_(3)=m" Eq of "H_(2)C_(2)O_(4)` `100mL xx0.2xx4=(1)/(4)xx2xxV mL` `V_(H_(2)C_(2)O_(4))=160 mL` `N_(KAl(OH)_(2)CO_(3))=0.1xx4=0.8N` |
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