1.

100 ml of 1 M H_(2) SO_(4) solution (d_("solution") = 1.5 gm//ml) is mixed with 400 ml of water (d_("water") = 1 gm //ml) then molarity of final solution (d_("final solution") = 1.25 gm//ml) is -

Answer»

0.227 M
2.5 M
0.4 M
2.27 M

Solution :Mass of `H_(2)SO_(4)` solution `= 100 xx 1.5 = 150 gm`
Mass of water `= 400`
Mass (total) `= 550 gm`
MOLES of `H_(2)SO_(4) = 0.1` mole
VOLUME finally `= (550)/(1.25) = 440 mL`
`M = (0.1)/(440) xx 1000 = 0.227 M`


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