1.

100 ml of a gaseous mixture containing CO and CH_(4) shows a volume contraction of 65 ml on combustion in excess of O_(2). Then what will be the volume of CO (g).

Answer»

`10 mL`
`40 mL`
`90 mL`
`20 mL`

SOLUTION :`{:(,2 CO (G),+,O_(2) (g) RARR,,2 CO_(2) (g),,,),("volume",x mL,,(x)/(2) mL,,x mL,,,),(,CH_(4) (g) +,2O_(2) (g),,rarr,CO_(2) (g),+,2H_(2)O (l),),("volume",(100 - x) mL,2 (100 - x) mL,,(100 - x) mL,,2 (100 - x) mL,,):}`
Volume contraction `= 2 (100 - x) + (x)/(2) = 65`
`x = 90 mL`


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