100 ml of a gaseous mixture containing Ne,CO_(2) & H_(2) on complete combustion in just sufficient amount of O_(2) showed contraction of 60 ml at NTP. When the resulting gases were passed through KOH solution, volume reduce by 40%. The volume ratio of V_(co_(2)):V_(Ne):V_(H_(2)) in original mixture is:

100 ml of a gaseous mixture containing Ne,CO_(2) & H_(2) on complete c

1.	100 ml of a gaseous mixture containing Ne,CO_(2) & H_(2) on complete combustion in just sufficient amount of O_(2) showed contraction of 60 ml at NTP. When the resulting gases were passed through KOH solution, volume reduce by 40%. The volume ratio of V_(co_(2)):V_(Ne):V_(H_(2)) in original mixture is:
Answer» `10:9:2` `6:9:10` `7:3:10` None Solution :`100mlrarrH_(2)+CO+Ne` `H_(2)+1//2O_(2)rarrH_(2)O(l)` x x/2 `DeltaV_("contraction")=x+(x)/(2)=(3X)/(2)=60` `rArrx=40ml` Total initial volume `=V_("mix")+V_(O_(2))` =100+20=120ml Volume of resulting gases=120-60=60ml `40% "of" 60ml=(40)/(100)xx60=24ml` `V_(Ne)=60-40=36` `V_(CO_(2)): V_("Ne"): V_(H_(2))=6:9:10`