1.

100 mL of an aqueous solution of protein contais 6.3 g of protein. Calculate the molar mass of protein if osmatic pressure of the solution at 27^@C is 2.57 xx 10^(-3) bar.

Answer»

Solution :Osmotic pressure `pi=2.57xx10^(-3)` BAR ,
weight of solute = W= 6.3 g
Solution constant =S=0.083 L bar `K^(-1) "mol"^(-1)`
Volume of solution =V=100mL = 0.1 L : Absolute TEMPERATURE =300 K
MOLAR mass =`(wST)/(piV)=(6.3xx0.083xx300)/(2.57xx10^(-3)xx0.1)="610 g mol"^(-1)`


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