1.

100 mL of tap water containing Ca(HCO_(3)_(2) was titrated with (N)/(50)HCL with methyl orange as indicaor. If 30 mL of HCL was required, the temporary hardness of water as parts of CaCO_(3) per 10^(6) parts of water was

Answer»

150 ppm
600 ppm
275 ppm
300 ppm

Solution :Meq of `CaCO_(3)` = Meq. Of `Ca(HCO_(3))_(2)` = Meq. Of HCl
`(w)/(100//2)xx1000=(1)/(50)xx30`
`w_(CaCO_(3))=(3xx100)/(5xx2000)=0.03 g`
`THEREFORE` 100 g ML of `H_(2)O` CONTAINS `Ca^(2+)=0.03g`
`10^(6)mLH_(2)O" contains "Ca^(2+)=(0.03xx10^(6))/(100)=300"ppm"`


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