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1000 gm water is heated from `27^(@)` C to `47^(@) C` at a constant pressure of 1 bar . The coefficient of volume expansion of water is `0.002//^(@)`C and the molar volume of water at `0^(@)` is `18.00cm^(3)//"mol"`. The magnitude of work done (in J) by water is |
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Answer» `V_(t^(@)C)= V_(0^(@)C) (1 +gammat)" "gamma="coefficient of volue expansion "` `V_(27^(@)C)= 1000 (1 +0.002 xx27)" "t =" temperature in ".^(@)C ` `= 1054 ml` `V_(47^(@)C) =1000 (1 + 0.002 xx 47)` `=1094 ml` `W =-PDeltaV =(-1 xx(1094 - 1054))/(1000)"bar litre" =(-4)/(100) "bar litre"=(-4)/(100) xx100J = - 4 J` |
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