1.

10000000000000000000000000000000000000000000 Points1) Find the curved and surface area and volume of the cone whose radius of base 21 cm and height 28cm?

Answer»

\huge{\bf{\underline{\red{Solution :}}}}

GIVEN,

To Find,

  • CURVED SURFACE area = ?
  • Total surface area = ?
  • Volume of the cone = ?

Find,

⇒Firstly we find the slant height of the cone .

∴Slant height of the cone( l ) = \bold{\sqrt{r^{2} + h^{2} }}

\implies \bold{l = \sqrt{  21^{2} + 28^{2}  }}

\implies \bold{ l =  \sqrt{ 441 + 784}}

\implies \bold{l = \sqrt{  1225}}

\implies \boxed{\bold{ l = 35 \ cm }}

Now Curved Surface Area :-

\implies \boxed{\bold{ Curved \ Surface \ Area = \pi rl}}

\implies \bold{\frac{22}{7} \times 21 \times 35}

\implies \boxed{\bold{2310 \ cm^{2}}}

Now Total Surface Area :-

\implies \boxed{\bold{Total \ surface \ Area = \pi r(l + r})}

\implies \bold{\frac{22}{7} \times 21(35 + 21)}

\implies \bold{22 \times 3 \times 56 }

\implies \boxed{\bold{3696 \ cm^{2}}}

Now Find the Volume of the Cone :-

\implies \boxed{\bold{ Volume \ of \ the \ cone = \frac{1}{3} \times \pi r^{2} h}}

\implies \bold{\frac{1}{3} \times \frac{22}{7} \times 21 \times 21 \times 28}

\implies \bold{22 \times 3 \times 7 \times 28}

\implies \boxed{\bold{12936 \ cm^{3}}}

\rule{200}2



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