1.

100mL of a solution containning 5 g of NaOH is mixed with 200 mL of M/5 NaOH solution. Calculate the molarity of the resuliting solution.

Answer»


SOLUTION :Mass os NaOH in 200 mL of M/5 NaOH solution
`"Molarity of solution"=("Mass os NaOH(W)/Molar mass")/("Volume of solution in LITRES")`
`(1//5" mol L"^(-1))=W/((40" g mol"^(-1))XX(0.2L))`
`W=(1//5" mol L"^(-1))xx(40" g mol"^(-1))xx(0.2 L)=1.6 g`
Step II. Molarity of MIXTURE solution
Total mass of NaOH = 1.6 + 5.0 =6.6 g
Total volume of solution = 200 + 100 = 300 mL
`"Molarity (M)"=("Mass os NaOH/Molar mass")/("Volume of solution is litres")=((6.6g)//(40" g mol"^(-1)))/((300//1000 L))`
`0.55" mol L^(-1)=0.55 M`


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