1.

10800 C of electricitythrough the electrolyte deposited 2.977 g of metal with atomic mass 106.4 g mol^(-1). Find the charge on the metal cations.

Answer»


Solution :`M^(N+) + n e RARR M`
For `M, (w)/(E) = (it)/(96500)"" ( :' Q = i XX t)`
`(2.977)/(106.4//n) = (10800)/(96500)`
`:. n = (106.4 xx 10800)/(2.977 xx 96500) = 4`


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