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`10cm^(3)` of 0.1N monobasic acid requires `15cm^(3)` of sodium hydroxide solution whose normality isA. `1.5N`B. `0.15N`C. `0.066N`D. `0.66N` |
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Answer» Correct Answer - C `{:(N_(1)V_(1),=,N_(2)V_(2)),(("For monobasic acid"),,("For NaOH")):}` `10xx0.1N=15xxN_(2)` `N_(2)=(1N)/(15)=0.066N` |
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