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Two solutions of HCl, A and B have concentration of 0.5 N and 0.1 M respectively . The volume of solutions A and B required to make 2 L of 0.2 N HCl areA. `0.5L" of " A+1.5L" of " B`B. `1.5L" of " A+0.5L" of " B`C. `1.0L" of " A+1.0L" of " B`D. `0.75L" of " A+1.25L" of " B` |
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Answer» Correct Answer - A `N_(A)=0.5,V_(A)=VL("let")` `N_(B)=M_(B)=0.1,V_(B)=(2-V)L` From normality equation, `NV=N_(A)V_(A)+B_(B)V_(B)` `0.2xx2=0.5xxV+0.1xx(2-V)` `0.4=0.5V+0.2-0.1V` `0.4V=0.2` `V=(0.2)/(0.4)=0.5` `:.V_(A)=0.5L` `" and "V_(B)=(2-05)=1.5L` |
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