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`K_(f)` for water is `1.86 K kg mol^(-1)`. IF your automobile radiator holds `1.0 kg` of water, how many grams of ethylene glycol `(C_(2)H_(6)O_(2))` must you add to get the freezing point of the solution lowered to `-2.8^(@)C` ?A. 72 gB. 93 gC. 39 gD. 27 g |
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Answer» Correct Answer - B Coolant glycol `(C_(2)H_(6)O_(2))` is a non-electrolyte. `DeltaT_(1)=2.8^(@)` `DeltaT_(1)=(1000K_(f)w_(1))/(m_(1)w_(2))rArr2.8=(1000xx1.86xxw_(1))/(62xx1000)` `:.w_(1)=93.33g` |
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