1.

10g hydrogen and 64 g oxygen were filled in a steel vessel and exploded, Amoung of water produced in this reaction will be

Answer»

3 mol
4 mol
1 mol
2 mol

Solution :`n_(H_(2))=(10)/(2)=5 n_(O_(2))=(64)/(32)=2`
`2H_(2)+O_(2)rarr2H_(2)O`
CaseI: If `H_(2)` is completely consumed, then `n_(H_(2)O)=5`mol
CaseII: If `O_(2)` is completely consumed, then
`n_(H_(2)O)=(2)/(1)xx2=4` mol
Since,`O_(2)` gives least amount of product on complete consumption HENCE, it is limiting and number of moles of water formed will be equal TO4.


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