1.

`11.2 "litre"` of a gas `STP` weighs `14 g`. The gases would be:A. `N_(2)`B. `CO`C. `N_(2)O`D. `B_(2)H_(6)`

Answer» Correct Answer - A::B::D
Molecular weight of gas `=(14xx22.4)/(11.2)=28`
i.e., `CO,N_(2),B_(2)H_(6)`


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