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11. A gaseous hydrocarbon given upon combustion 0.72 g of water and 3.08 g. of CO2. The empirical formula ofthe hydrocarbon is:(a) Ciha (1) C: H, (C) CCM, (d) C; Hz

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1 is a roght ansure

A hydrocarbon is consist of C and H and empirical formula can be written as CxHy.To find the empirical formula, you have to find the moles of C and Hrelesed in form of H2O and CO2.18 g H2O contain 2 moles of H atoms⇒0.72 gram of H2O will contain = 2/18 x 0.72 = 0.08 moles of H​44 g of CO2contain 1 mole of C atom⇒3.08 gramof CO2 will contain 1/44 x 3.08 = 0.07 moles of C​Ratio of x and y = 0.07/0.08 = 7 : 8So the empirical formula will be: C7H8



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