InterviewSolution
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`1,1+I,2i,-2+2i,"…."i= sqrt(-1)` |
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Answer» Here, `a=1` and `r=(1+i)/(1)=(2i)/(1+i)=(-2+2i)/(2i)="..."` `=(1+i)=(2i(1+i))/((1+i)(1+i))=((-1+i)i)/(i)^(2)="..."` `=(1+i)=(1+i)=(1+i)="..."` `i.e.,a=1,r=1+i` Imaginary GP `(r= " imaginary ")` |
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