If 1=11, 2=22, 3=33, 4=44, 5=55, 6=66, 7=77, then 11=?Earn reward points on online shopping* & much more.the answer is 112my explanation: 1=(the number =1)+summation(1)=11 ,TEST 1*2=2 sum of 11=2 ;2 =(the number =2)+summation(2)=22 ,test 2*2=4 sum of 22=4 ;3 =(the number =3)+summation(3)=33 ,test 3*2=6 sum of 33=6 ;4 =(the number =4)+summation(4)=44 ,test 4*2=8 sum of 44=8 ;5 =(the number =5)+summation(5)=55 ,test 5*2=10 sum of 55=10 ;6 =(the number =6)+summation(6)=66 ,test 6*2=12 sum of 66=12 ;7 =(the number =7)+summation(7)=77 ,test 7*2=14 sum of 77=14 ;….10=(the number =10)+summation(1)=101 ,test (1+0)*2=2 sum of 101=211=(the number =11)+summation(2)=112 ,test (1+1)*2=4 sum of 112=4second demonstration:1=11, 2=22 ,3=33, 4=44, 5=55…..10=101, 11=112from 1=11 to 9=99 are 9 numbers =+11 THAT IS11+11=22, 22+11=33, 33+11=44….from 9=99 to 10=101 is 1 number=+2 THAT IS 99+2=101from 10=101 to 18=189 are always 9 numbers=+11In conclusion SEQUENCE is repeating cycle :the first nine numbers(+11) then tenth number(+2)the second nine numbers(+11) then tenth number(+2)the third nine numbers(+11) then tenth number