11. In an election, candidate A has secured 12% votes more than candidate B. By how much per cent has candidate B less than candidate A?pl help me

11. In an election, candidate A has secured 12% votes more than candid

1.	11. In an election, candidate A has secured 12% votes more than candidate B. By how much per cent has candidate B less than candidate A?pl help me
Answer» Team B has 10 5/7% (10 whole 5 by 7%) less votes than team A.Step-by-step EXPLANATION:No. of people in an election=y(Let the total no. of VOTERS be y)Percentage of candidates team A has secured more than team B=12%Therefore, No of candidates team B less than team A=Let total votes for team B = xTherefore, No. of Votes for team A = X + 12x/100 (x+12=12x)Total no. of votes for team A = 112x/100(28x/25)Percentage of team B less than team A=(equation)(28x/25-x)/28x/25×100=3x/25 × 25/28x × 100300/28%=(150/4%)={75/7%}=> 10 5/7% (10 whole 5 by 7%)Answer= Out of Y(the total POPULATION) Team B has got 10 5/7% less votes than team A.