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11. One gram of water (em) becomes 1671cm2 of steam when boiled at a constant pressure of latm(1.013x 10'Pa). The heat of vaporization at this pressue is , -2,256x 10 J/kg Compute (a) theworkdonebythewaterwhenitvaporizesand(b)itsincrease ininternal energy |
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Answer» Work done = pressure x change in volume= 1.013 x 10^5 x (1670 x 10^-6 m^3)= 169.2 J (correct to 4 significant figures) Increase in internal energy = latent heat of vaporisation - work done by the water.= 2.256 x 10^3 - 169.2 = 2087 J (correct to 4 significant figures) |
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