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11) similary A (B nc) = (A-B) u (A-C) |
Answer» Answer:A - (B n C) = (A - B) U (A - C).<P>Step-by-step explanation:For any three sets A, B and C, we are given to PROVE the following :A - (B ∩ C) = (A - B) U (A - C).We know thatany two sets P and Q are EQUAL if and only if both are subsets of each other, that isP ⊂ Q and Q ⊂ P.Let us consider thatX ∈ A - (B ∩ C)⇒x∈A, x ∉ (B ∩ C)⇒x∈A, (x∉B or x∉C)⇒(x∈A, x∉B) or (x∈A, x∉C)⇒x∈(A-B) or x∈(A-C)⇒x∈(A-B) ∪ (A-C)So, A - (B n C) ⊂ (A-B) U (A-C).Again, letx∈(A-B) ∪ (A-C)⇒x∈(A-B) or x∈(A-C)⇒(x∈A, x∉B) or (x∈A, x∉C)⇒x∈A, (x∉B or x∉C)⇒x∈A, x ∉ (B ∩ C)⇒x ∈ A - (B ∩ C).So, A - (B ∩ C) ⊂ (A-B) ∪ (A-C).Therefore, we getA - (B n C) = (A - B) U (A - C).Hence proved. |
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