11. The diameters of three circles are in the ratio 3:5:6. If the sum of the circumferences of these circles be 308 cm; find the difference between the areas of the largest and the smallest of these circles.

11. The diameters of three circles are in the ratio 3:5:6. If the su

1.	11. The diameters of three circles are in the ratio 3:5:6. If the sum of the circumferences of these circles be 308 cm; find the difference between the areas of the largest and the smallest of these circles.
Answer» ANSWERGiven,Diameter of three circle=3:5:6Sum of the circumference=308cmLet the diameter of the CIRCLES be 3X,5x,6xNow, π(3x)+π(5x)+π(6x)=308=>14xπ=308=>x= 2×22308 =>x=7Therefore,Diameter of the largest side=6×7 =42Radius of largest circle= 26×7 =21Diameter of the smallest circle=3x =3×7 =21Radius of smallest circle= 23×7 =10.5Difference of areas of largest and smallest of the circles=π(21) 2 −(π(10.5) 2 =1039.5cm 2 Answered Bytoppr82 ViewsHow satisfied are you with the ANSWER?This will help us to improve betteranswrGet Instant SOLUTIONS, 24x7No Signup requiredgirlMore Questions by difficultyEASYMEDIUMHARD

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11. The diameters of three circles are in the ratio 3:5:6. If the sum of the circumferences of these circles be 308 cm; find the difference between the areas of the largest and the smallest of these circles.

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