1104. In Fig. 6.31. if PQ I ST, PQR = 110° andRST=130°, find 2 QRS.[Hint : Draw a line parallel to ST throughpoint R.)Fig. 6.31

1104. In Fig. 6.31. if PQ I ST, PQR = 110° andRST=130°, find 2 QRS.[

1.	1104. In Fig. 6.31. if PQ I ST, PQR = 110° andRST=130°, find 2 QRS.[Hint : Draw a line parallel to ST throughpoint R.)Fig. 6.31
Answer» <p>Question 4. In Fig. 6.31, if PQ \|\| ST, ∠ PQR = 110° and ∠ RST = 130°, find ∠ QRS.</p><p>Question 4. In Fig. 6.31, if PQ \|\| ST, ∠ PQR = 110° and ∠ RST = 130°, find ∠ QRS.[Hint : Draw a line parallel to ST through point R.]</p><p>Solution:Let us draw a parallel line XY to PQ \|\| ST and passing through point R.Sum of interior angle on the same side of the transversal is always = 180°</p><p>So that∠ PQR + ∠ QRX = 180°Given that ∠ PQR= 110°110° + ∠QRX = 180°∠QRX = 180° -110°∠QRX = 70°Sum of interior angle on the same side of the transversal is always = 180°</p><p>∠RST + ∠SRY = 180° (Co-interior angles on the same side of transversal SR)Also130° + ∠SRY = 180°∠SRY = 50°XY is a straight line. Use property of linear pair we get∠QRX + ∠QRS + ∠SRY = 180°70° + ∠QRS + 50° = 180°∠QRS = 180° − 120°= 60°</p> <p>QRS = 110+130 =240 -180 = 60 so QRS= 60</p> <p>60° is right answer of this question. please like my answer </p> <p>60° is the correct answer</p>