1.

12. A ball is thrown upwards with an initial speed of 20ms-1. Calculate the maximumheight attained by it?​

Answer»

Time to reach maximum height can be obtained from v=u+at

0=20+(−10)t

t=2s

s=ut+0.5at

2

=20(2)+0.5(−10)(2)

2

=20m

Thus, total DISTANCE for maximum height is 45 m

s=ut+0.5at

2

45=0+0.5(10)(t

)

2

t

=3s

Total time= 3+2= 5s

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