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12. A ball is thrown upwards with an initial speed of 20ms-1. Calculate the maximumheight attained by it? |
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Answer»
Time to reach maximum height can be obtained from v=u+at0=20+(−10)tt=2ss=ut+0.5at2=20(2)+0.5(−10)(2)2=20mThus, total DISTANCE for maximum height is 45 ms=ut+0.5at245=0+0.5(10)(t′)2t′=3sTotal time= 3+2= 5sHI DEAR SHRESTA HERE PLEASE FOLLOW ME FRNDS AND THANK MY ANSWER TOOO..(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(●♡∀♡) |
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