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12. A father is 3 times as old as his son. After 15 years, he will be twice as old as his son, what are their present ages? |
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Answer» the son's present AGE Is 15 yearsStep-by-step explanation:Let the present age of son be X years Then, present age of other =3X yearsAfter 15 years :Son's age =(x+15) yearsFather's age =(3x+15) yearsBut, according to the question.⇒(3x+15)=2(x+15)⇒3x+15=2x+30⇒3x−2x=30−15⇒x=15∴ Son's age is 15 years. |
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