1.

12. Calculate the volume occupied by one molecule of water assuming the density ofwater be 1.0 g/mL.

Answer»

6.022*10^23 molecules=18 gm of water

Therefore,1 molecule=18/6.022*10^23 gm of. Water

=3.0*10^-23gm of water

We know, density=mass/volume

Volume=mass/density

=3.0*10^-23gm/1gm cm^-3

=3.0*10^-23 cm^3



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