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12. Calculate the volume occupied by one molecule of water assuming the density ofwater be 1.0 g/mL. |
Answer» <p>6.022*10^23 molecules=18 gm of water</p><p>Therefore,1 molecule=18/6.022*10^23 gm of. Water</p><p> =3.0*10^-23gm of water</p><p>We know, density=mass/volume</p><p> Volume=mass/density</p><p> =3.0*10^-23gm/1gm cm^-3</p><p> =3.0*10^-23 cm^3</p> | |