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12. Calculate the volume occupied by one molecule of water assuming the density ofwater be 1.0 g/mL. |
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Answer» 6.022*10^23 molecules=18 gm of water Therefore,1 molecule=18/6.022*10^23 gm of. Water =3.0*10^-23gm of water We know, density=mass/volume Volume=mass/density =3.0*10^-23gm/1gm cm^-3 =3.0*10^-23 cm^3 |
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