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12 cm 10 cm 18 cm find the area |
Answer» <html><body><p>21 √11sq cmStep-by-step <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a>:Given <a href="https://interviewquestions.tuteehub.com/tag/sides-1207029" style="font-weight:bold;" target="_blank" title="Click to know more about SIDES">SIDES</a> are 18cm,10cm and 14cmArea of <a href="https://interviewquestions.tuteehub.com/tag/triangle-1427233" style="font-weight:bold;" target="_blank" title="Click to know more about TRIANGLE">TRIANGLE</a> = s(s−a)(s−b)(s−c) ⇒a=18cm,b=10cm and c=14cm⇒s= 2a+b+c = 218+10+14 = <a href="https://interviewquestions.tuteehub.com/tag/242-296171" style="font-weight:bold;" target="_blank" title="Click to know more about 242">242</a> =21cmArea = 21(21−18)(21−10)(21−14) = 21×3×11×7 =21 √11sqcmHence, the answer is 21 √11sqcm.</p></body></html> | |