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12. Show that x=1 is a root of the polynomial 3x^3– 4x^2+7x – 6

Answer»

Answer:

Given that x= 1

P(x) = 3x^3 - 4x^2 + 7X - 6

p(1) = 3(1)^3 - 4(1)^2 + 7(1) - 6

p (1) = 3- 4 + 7 -6

p(1) = -1-6+ 7

p(1) = -7+7

p(1) = 0

Hence x=1 is a ROOT of the polynomial 3x^3 - 4x^2 + 7x - 6.


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