1.

127 ml of a certain gas diffuse in the same time as 100 ml of chlorine under the same conditions. Calculate the molecular mass of the gas.

Answer»

Solution :If t is the time taken for diffusion of each gas, then by Graham.s law of diffusion
`(r_(x))/(rCl_(2))=(127//t)/(100//t)=SQRT((M_(Cl_(2)))/(M_(x)))=sqrt((71)/(M_(x)))`
Or `(71)/(M_(x))=((127)/(100))^(2)`
or `M_(x) =44 u`


Discussion

No Comment Found

Related InterviewSolutions