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13. A particle is moving with velocity 5 m/s towards east and its velocity changes to 5 m/s north in 10 sec.Find the acceleration(A) v2 N-W1BN-W42(C)N-E12(D) 2 N-Ethn hodh attains a velocity of |
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Answer» Intial velocity=v1= 5m/seast wards ^||^then after time t=10sec || towards north 5m/sv2 =5m/s north wards .⇒⇒⇒⇒⇒⇒| towards east 5m/sVresultant =√v1²+v2² =√25+25 =5√2 acceleration a=velocity/time = 5√2/10 =√2/2 ×√2/√2 =1/√2 towards n-w |
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