1.

._(13)Al^(27) is a stable isotope. ._(13)Al^(29) is expected to disintegrate by

Answer»

`alpha` EMISSION
`_(-1)^(0) beta` emission
Positron emission
Proton emission

Solution :Since `._(13)^(27) Al` is stable isotope , `._(13)^(29)Al`has `(n)/(P)` RATIO higher than required, it will disintegrate by `beta^(-)` emission and `(n)/(P)` ratio will decrease.
`._(13)^(29)Al rarr ._(14) si^(29)+._(-1)E^(0)`


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