._(13)Al^(28) when radiated by suitable projectile gives ._(15)P^(31) – InterviewSolution

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1.	._(13)Al^(28) when radiated by suitable projectile gives ._(15)P^(31) and neutron. The projectile used is
Answer» Proton Neutron Alpha particle Deuteron Solution :`._(13)Al^(28) + ._(2)He^(4) rarr ._(15)P^(31) + ._(0)N^(1)`

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