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13. Find the HCF, by Euclid's division algorithm of the numbers 92690, 7378 and 7161

Answer»

By Euclid’s division algorithm,92690 = 7378 x 12 + 41547378 = 4154 x 1+ 32244154 = 3224 x 1 + 9303224 = 930 x 3 + 434930 = 434 x 2 + 62434 = 62 x 7 + 0Therefore, HCF (92690, 7378) = 627161 = 62 x 115 + 3162 = 31 x 2 + 0Therefore, HCF(7161, 62) = 31Hence, HCF (92690, 7378, 7161) = 31



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