1.

13. Find the sum of the first 15 multiples of 8.​

Answer»

Step-by-step explanation:

The first 8 multiples of 8 are

8,16,24,32,40,48.56,64...

These are in an A.P.having first TERM as 8 and common difference as 8

Therefore a=8

d=8

S15=?

Sn=n/2 (2a+ (n-1)d)

S15=15/2 (2(8)+ (15-1)8)

15/2(6+(14)(8))

15 (128)/2

15×64=960......

hope it helps U....

Mark me as brainalist......



Discussion

No Comment Found

Related InterviewSolutions