139. If 60% of a first order reaction wascompleted in 60 minutes, 50%

1.	139. If 60% of a first order reaction wascompleted in 60 minutes, 50% of thesame reaction would be completed inapproximately
Answer» Firstly find out rate of reaction K using,K=(2.303/60) * log (100/40)Now take this k, which come out to be 0.0152 per minute. For finding time for 50%, you can use any of the 2 approach: 1) you can use the same formual above and substitute the value of k to find time, here log will have different values. t= (2.303/0.0152)*log(100/50)t= 45.6 minutes. 2) you can use half life formula for first order reaction. t=0.693/kt=0.693/0.0152t=45.6 minutes. I hope this answers the question.

139. If 60% of a first order reaction wascompleted in 60 minutes, 50% of thesame reaction would be completed inapproximately

Answer»

Firstly find out rate of reaction K using,K=(2.303/60) * log (100/40)Now take this k, which come out to be 0.0152 per minute.

For finding time for 50%, you can use any of the 2 approach:

1) you can use the same formual above and substitute the value of k to find time, here log will have different values.

t= (2.303/0.0152)*log(100/50)t= 45.6 minutes.

2) you can use half life formula for first order reaction.

t=0.693/kt=0.693/0.0152t=45.6 minutes.

I hope this answers the question.