14. A bullet of mass 10 g travelling horizontally with a velocity of150 m s1 strikes a stationary wooden block and comes to restin 0.03 s. Calculate the distance of penetration of the bulletinto the block. Also calculate the magnitude of the force exertedby the wooden block on the bullet.

14. A bullet of mass 10 g travelling horizontally with a velocity of15

1.	14. A bullet of mass 10 g travelling horizontally with a velocity of150 m s1 strikes a stationary wooden block and comes to restin 0.03 s. Calculate the distance of penetration of the bulletinto the block. Also calculate the magnitude of the force exertedby the wooden block on the bullet.
Answer» <p>Data:mass of the bullet (m) = 10 g = (10/1000) kg =0.01 kgInitial velocity (u) = 150 m/sFinal velocity (v) = 0 m/sTime taken (t) = 0.03 sec</p><p>i. Calculation of the distance of penetrationof the bullet into the block: </p><p>Calculation of the distance of penetrationof the bullet into the block = Displacement</p><p>Displacement = average velocity × timeDisplacement = [(u + v) / 2] × timeDisplacement = [(150 + 0) / 2] × 0.03Displacement = 2.25 m</p><p>ii. Calculation of the magnitude of the force exerted by the wooden block on the bullet:the magnitude of the force exerted by the wooden block on the bullet = Retarding forceRetarding force = mass × reatardationRetarding force = mass ×[ (Intitial velocity - Final velocity) / t ]Retarding force = 0.01 ×[ (150 - 0) / 0.03 ] NRetarding force = [150/3] NRetarding force = 50 N</p> <p>thanks </p>