14.Factorize 2x² – 5 xy + 3y²} and use your result tofactorize 2(3

1.	14.Factorize 2x² – 5 xy + 3y²} and use your result tofactorize 2(3a- b)²– 5 (3a-b) (2a-b)+3(2a-b)².The factors are
Answer» Answer: AB Step-by-step explanation: Given an algebraic expression such that, $2 {x}^{2} - 5xy + 3 {y}^{2}$ To FACTORISE it, We will use MIDDLE term splitting method. Therefore, we will get, $= 2 {x}^{2} - 2xy - 3xy + 3 {y}^{2} \\ \\ = 2x(x - y) - 3y(x - y) \\ \\ = (x - y)(2x - 3y)$ Now, another expression is such that, $2 {(3a - b)}^{2} - 5(3a - b)(2a - b) + 3 {(2a - b)}^{2}$ Let's assume that, x = (3a-b) y = (2a-b) Therefore, we have, $= 2 {x}^{2} - 5xy + 3 {y}^{2}$ Factorising this as same as above is DONE, Therefore, we will get, = {(3a-b)-(2a-b)}{2(3a-b)-3(2a-b)} = (3a-b-2a+b)(6a-2b-6a+3b) = ab Hence, the REQUIRED value is ab.