1.

(15)/(16)th of a radioactive sample decays in 40 days. Half-life of the sample is

Answer»

100 days
10 days
1 day
`log_(E) 2` days

Solution :Quantity of radioactive ELEMENT decayed = `(15)/(16)`
Quantity LEFT `= 1 - (15)/(16) = (1)/(16)`
`(1)/(16) = 1 XX ((1)/(2))^(n) or ((1)/(2))^(4) = ((1)/(2))^(n)`
one half-life `= (40)/(4) = 10` days.


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