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15.Avehicle of mass 1000 kg moving with a velocity of20 m/s is brought to rest in 5 seconds after coveringa distance of 50 m.a. Find the accelerationb. Calculate the unbalanced force acting on thevehicle.c. The actual force applied by the brakes may beslightly less than that calculated in (b). Why? Givereason.

Answer» <p>Data: mass of the body = 1,000 kg Initial velocity (u) = 20 m/s Final velocity (v) = 0 m/s Displacement (S) = 50 m Force acting (F) =?Solution:</p><p>We know that F = ma and 2as=v2- u2 ⇒ 2 × a × 50 m = 02- 202</p><p>a= -4 m/s2now F = ma ⇒F = 1,000 × -4 = -4,0000N</p><p>Note: Negative symbol represents The opposit direction to the displacement.</p> <p>correct answer is -4, 0000Nplease like❤❤❤️👍</p>


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