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InterviewSolution
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15 gm of a substance dissolved in 150 gms of water produces a depression of -1.2^@ C in the freezing point . Calulation the Mol. Wt. of the solid ( K_f for water is 1.86 K kg mol ^(-1) ) |
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Answer» Solution :`Delta T_f =K_f XX w/M xx 100/W` < br> `implies12 =18.5xx15/Mxx100/ 150` `implies M = (18.5xx15xx100)/(1.2xx150)` `= 154.16 gm mol^(-1)` |
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