1.

15 gm of a substance dissolved in 450 gms of water produces a depression of -0.34^@ C in the freezing point . Calulation the Mol. Wt. of the solid ( K_f for water is 1.86 K kgmol ^(-1))

Answer»

Solution :`DELTA T_f =K_f XX w/M xx 100/W` < br> `implies12 =18.5xx15/Mxx100/ 150`
`IMPLIES M = (18.5xx15xx100)/(1.2xx150)`
`= 154.16 gm MOL^(-1)`


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