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15. In a trapezium ABCD, seg AB || seg DC,seg BDI seg AD, seg ACI seg BC, if AD = 15,BC = 15 and AB = 25. Find A(O ABCD).Note :1.By use pytha. theorem |
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Answer» Answer: 192 sq.UNITS Step-by-step explanation: according according to PYTHAGORAS theoremtriangleABD AB²= AD² +BD² BD²=AB²-AD² BD=20 Now, Area of triangle ABD = √S(S-a) (S-b) (S- c) S= a+b+c/2S=30 Area of triangle =√S(S-a) (S-b) (S- c) Area of triangle = 150 sq . units DP = 300 /25 ......... (1/2*BASE *HEIGHT) DP=12 therefore height of trapezium is 12 Now according to pythagoras theoremIn triangle ADP AD²=AP²+DP² AP²=AD²- AP²=224-144 AP=9 therefore AP= QB=9 CD=PQ=7 area of trapezium =1/2 * some of parallel sides * height =192 sq.units hence area of trapezium ABCD is 192 sq.units I hope it helped you Please Please Please Mark Me As Brainlist Please |
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