1.

15% of oxygen is converted to ozone. The mass of ozone that can be prepared from 67.2 L of oxygen at N.T.P. will be

Answer»

14.4 g
28.8 g
52.0 g
64 g

Solution :`underset("3 vol")(3O_2) to underset("2vol")(2O_3)`
67.2 L of `O_2` produces OZONE =` (2 XX 67.2)/(3) = 44.8 L`
sicne of efficiency is only 15%
`O_3` produced ` = (44.8 xx 15)/(100) = 6.72 L`
mass of `O_3` produced ` = (6.72 xx 48)/(22.4)= 14.4 g `


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