`150 mL` of `0.5N` nitric acid solution at `25.35^(@)C` was mixed with `150 mL` of `0.5 N` sodium hydroxide solution at the same temperature. The final temperature was recorded to be `28.77^(@)C`. Calculate the heat of neutralisation of nitric acid with sodium hydroxide.

`150 mL` of `0.5N` nitric acid solution at `25.35^(@)C` was mixed with

1.	`150 mL` of `0.5N` nitric acid solution at `25.35^(@)C` was mixed with `150 mL` of `0.5 N` sodium hydroxide solution at the same temperature. The final temperature was recorded to be `28.77^(@)C`. Calculate the heat of neutralisation of nitric acid with sodium hydroxide.
Answer» Total mass of solution `=150+150=300g` Q=total heat produced `=300xx(28.77-25.35)cal` `=300xx3.42=1026cal` Heat of neutralisation `=(Q)/(150)xx1000xx(1)/(0.5)` `=(1026)/(150)xx1000xx(1)/(0.5)=13.68kcal` Since, heat is liberated, heat of neutralisation should be negative. so, heat neutralisation `=-13.68kcal`

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`150 mL` of `0.5N` nitric acid solution at `25.35^(@)C` was mixed with `150 mL` of `0.5 N` sodium hydroxide solution at the same temperature. The final temperature was recorded to be `28.77^(@)C`. Calculate the heat of neutralisation of nitric acid with sodium hydroxide.

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