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(16^-2*4^3)/(8^-2)Please Answer |
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Answer» 16^-2*4^3/8^-2=(2^4)^-2*(2^2)^3/(2^3)^-2=2^-8*2^6/2^-6=2^(-8+6)/2^-6. [a^m*a^n=a^(m+n)]=2^-2/2^-6=2^[(-2)-(-6)]. [a^m/a^n=a^(m-n)]=2^(-2+6)=2^4=16Hope it HELPS |
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