16. A tent is in the form of a Cylinder of diameter 4.2m and Height 5m

1.	16. A tent is in the form of a Cylinder of diameter 4.2m and Height 5m.And a Right Circular Cone above it. And cone of equal base andSlant Height 2.8m. Find the total surface area for making the tent.Also find the cost of Canvas for making tent at @ Rs.500 per sq.m.h 5m
Answer» Step-by-step explanation: Given: Height (h) of the cylindrical part = 2.1 m Diameter of the cylindrical part = 4 m Radius of the cylindrical part = 2 m Slant height (l) of CONICAL part = 2.8 m Area of CANVAS USED = CSA of conical part + CSA of cylindrical part =πrl+2πrh =π×2×2.8+2π×2×2.1 =2π[2.8+4.2] =2× 7 22 ×7 =44m 2 COST of 1 m 2 canvas =500 rupees Cost of 44 m 2 canvas =44×500=22000 rupees. Therefore, it will cost 22000 rupees for making such a tent.

16. A tent is in the form of a Cylinder of diameter 4.2m and Height 5m.And a Right Circular Cone above it. And cone of equal base andSlant Height 2.8m. Find the total surface area for making the tent.Also find the cost of Canvas for making tent at @ Rs.500 per sq.m.h 5m

Answer»

Step-by-step explanation:

Given:

Height (h) of the cylindrical part = 2.1 m

Diameter of the cylindrical part = 4 m

Radius of the cylindrical part = 2 m

Slant height (l) of CONICAL part = 2.8 m

Area of CANVAS USED = CSA of conical part + CSA of cylindrical part

=πrl+2πrh

=π×2×2.8+2π×2×2.1

=2π[2.8+4.2]

=2×

×7

=44m

COST of 1 m

canvas =500 rupees

Cost of 44 m

canvas =44×500=22000 rupees.

Therefore, it will cost 22000 rupees for making such a tent.