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InterviewSolution
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16 g of an ideal gas so, occupies 5.6 L. at STP. The value of x is(2) x 2(3) x = 4(4) none of these |
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Answer» We know that at S.T.P, 1 mole of eachideal gasoccupies the volume of 22.4 lit. So that,5.6 litgasis occupied by 5.6/22.4 =0.25 mole. On the other hand 0.25 mole=16g,so 1 mole=16/0.25=64g. As we know the whole atomic mass ofSOx=1 moleSOx=64,so 32+16x=64,or,x=2. |
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