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16. The number of molecules in 100 mL of o.04 NH,S04 is(1) 12.046x 1020 (2) 6.023 x 10(3) 3.011 x 102(4) 12.046 x 103

Answer»

Normality = molarity× Valance here valance = 2.

so, M = N/2 = 0.04/2 = 0.02Moles/L

no..of molecules will be 0.02*(6*10^23) = 12.04*(10^20) option A



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