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17.18. Find the difference in Cl and S.1 for P-28000.-= 5% pa- 2 yearsn = 3 years |
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Answer» <P>Step-by-step EXPLANATION: P = Rs 42000 T=2 years Let RATE = r % S.I= 100 PRT
= 100 42000×r×2
=840 Rs For C.I A=P(1+ 100 r
) n
=42000(1+ 100 r
) 2
=42000(1+ 10000 r 2
+ 50 r
) =42000+ 10 42r 2
+840r C.I = A - P =42000+ 10 42r 2
+840r−42000 = 10 42r 2
+840r Given C.I−S.I=105 = 10 42r 2
+840r−840r=105 = 10 42r 2
=105 =42r 2 =1050 =r 2 =25 r=5% C.I at 2nd year = 42000(1+ 100 5
) 2 −42000 =42000(1.1025−1)=4305 Rs |
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