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18.24*1.6 (With process) |
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Answer» -step explanation:The half-life period of a FIRST order process is 1.6 min. It will be 90% completed inMissing: 18.24* | Must INCLUDE: 18.24*TOP ANSWER · 198 votes0.8 min 3.2 min 5.3 min 1.6 min Answer: C Solution: For first order reaction, `t_(1//2)=(0.693)/(k)` `implies " "k=(0.693)/(1.6)=0.4332" min"^(-1)` Now, |
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